0.01=(-32^2x/130^2)+x

Solution for 0.01=(-32^2x/130^2)+x equation:

0.01=(-32^2x/130^2)+x

We move all terms to the left:

0.01-((-32^2x/130^2)+x)=0


Domain of the equation: 130^2)+x)!=0

x!=0/1

x!=0

x∈R


We multiply all the terms by the denominator


-((-32^2x+(0.01)*130^2)+x)=0


We calculate terms in parentheses: -((-32^2x+(0.01)*130^2)+x), so:

(-32^2x+(0.01)*130^2)+x

We add all the numbers together, and all the variables

x+(-32^2x+(0.01)*130^2)


We calculate terms in parentheses: +(-32^2x+(0.01)*130^2), so:

-32^2x+(0.01)*130^2

We add all the numbers together, and all the variables

-32^2x+169

Back to the equation:

+(-32^2x+169)


We get rid of parentheses

x-32^2x+169

Back to the equation:

-(x-32^2x+169)


We get rid of parentheses

-x+32^2x-169=0

We add all the numbers together, and all the variables

-1x+32^2x-169=0

We move all terms containing x to the left, all other terms to the right

-1x+32^2x=169